9r^2+37r+4=0

Solution for 9r^2+37r+4=0 equation:

9r^2+37r+4=0

a = 9; b = 37; c = +4;
Δ = b2-4ac
Δ = 372-4·9·4
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-35}{2*9}=\frac{-72}{18}
=-4
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+35}{2*9}=\frac{-2}{18}
=-1/9
$